Two players rushing one wonder

[IML Owl]

If two players rush a wonder in the same turn, how does the game decide which players gets it and which one just bought a ton of hammers?

[Hellogoodbye123]

i'm wondering on that question too, but i heard some guy say that the game goes through a "internal coin flip" thing, ones head and ones tails...and the game decided what side you are....

each get a 50/ 50 chance of getting it, its never happened to me....

were you building the hanging gardens, while you need one turn left and did next turn it said:

"The (enter enemy civ) have completed the hanging gardens" in the city of"

[Berrule]

Interesting question... beyond the simultaneous turns that do occur I supsect there is still a turn based engine at heart, whoever gets that benefit would get the wonder in the very rare case that 2 civs complete the same wonder in the same turn.

[Hellogoodbye123]

Interesting question... beyond the simultaneous turns that do occur I supsect there is still a turn based engine at heart, whoever gets that benefit would get the wonder in the very rare case that 2 civs complete the same wonder in the same turn.

what if all 5 rush the same wonder.......

[MrLowcash]

If you play against the AI, the AI gets it. I have used save and reload the 4x-check this...

I think logically, the one with the most hammer-leftover, would be the one to build it first, just slightly tiny little first. yes..

[xbman22x]

If you play against the AI, the AI gets it. I have used save and reload the 4x-check this...

I think logically, the one with the most hammer-leftover, would be the one to build it first, just slightly tiny little first. yes..

when you rush wonders, you have no hammer leftover.

[MrLowcash]

when you rush wonders, you have no hammer leftover.

You get to have the hammers for the next thing you produce, but i get your point. So there is a coin flip, or a x4 coin flip I suppose is fair amongst humans. If the AI is finishing a wonder, it takes it even if you buy it a turn ahead, in SP games.

[munchingfoo]

I think there is an order in which the computer does the maths at the end of each turn fr each city based on the position of the city. Although the map to us is cyclical to the computer it is likely represented as a rectangle with a series of boxes along and down, like graph paper. I believe it starts at the top left of these boxes in the rectangle shape and works it's way down the boxes, then moves one box to the right and repeats.

You can test (to some extent) by rushing the wonder in two of your own cities twice. You will find that the same city gets the wonder. This city is furthest left and up (given a tie break in the left direction) on the computer's box matrix representation of the map. You can actually see the order of your cities by having a building produced on the same turn in every one of them. When you get the automatic jumping between cities for the "what shall we build in this city" bit, that order is the order used for deciding wonder building too.

This also explains why the AI would always get the wonder when saved and retried, as described above. Remember also that the game uses a random seed starting point but then moves along it's random number table from that point in a deterministic fashion, therefore even if it was a random act, there would be no point in saving and reloading. You would always get the same result.